Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Find the roots
- Solve for x
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find break even points
- Load more...
Find the roots of the polynomial $\left(x^2-12x+36\right)^2$ by putting it in the form of an equation and then set it equal to zero
Learn how to solve equations problems step by step online.
$\left(x^2-12x+36\right)^2=0$
Learn how to solve equations problems step by step online. Find the roots of (x^2-12x+36)^2. Find the roots of the polynomial \left(x^2-12x+36\right)^2 by putting it in the form of an equation and then set it equal to zero. Removing the variable's exponent raising both sides of the equation to the power of \frac{1}{2}. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=-12 and c=36. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying.
