Final answer to the problem
$x=\frac{2+\sqrt{68}}{2},\:x=\frac{2-\sqrt{68}}{2}$
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Step-by-step Solution
How should I solve this problem?
- Find the integral
- Solve for x
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
- Find break even points
- Load more...
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1
Subtract the values $-8$ and $-8$
$x^2-2x-16=0$
Learn how to solve quadratic equations problems step by step online.
$x^2-2x-16=0$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation x^2-2x+-8+-8=0. Subtract the values -8 and -8. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=-2 and c=-16. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-).
Final answer to the problem
$x=\frac{2+\sqrt{68}}{2},\:x=\frac{2-\sqrt{68}}{2}$
