Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Product of Binomials with Common Term
- FOIL Method
- Find the integral
- Find the derivative
- Factor
- Integrate by partial fractions
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
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Expand the binomial $\left(2x^2+1\right)^4$
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$\left(5x-1\right)^3\left(\left(2x^2\right)^4+4\left(2x^2\right)^3+6\left(2x^2\right)^2+8x^2+1\right)$
Learn how to solve problems step by step online. Expand the expression (5x-1)^3(2x^2+1)^4. Expand the binomial \left(2x^2+1\right)^4. The power of a product is equal to the product of it's factors raised to the same power. The cube of a binomial (difference) is equal to the cube of the first term, minus three times the square of the first by the second, plus three times the first by the square of the second, minus the cube of the second term. In other words: (a-b)^3=a^3-3a^2b+3ab^2-b^3 = (5x)^3+3(5x)^2(-1)+3(5x)(-1)^2+(-1)^3 =. The power of a product is equal to the product of it's factors raised to the same power.