Simplify the expression with radicals $\left(\sqrt[3]{3}+1\right)\left(\sqrt[3]{9}-\sqrt[3]{3}+1\right)$

Step-by-step Solution

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Final answer to the problem

$\left(\sqrt[3]{\left(3\right)^{2}}-\sqrt[3]{3}+1\right)\sqrt[3]{3}+\sqrt[3]{\left(3\right)^{2}}-\sqrt[3]{3}+1$
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Step-by-step Solution

How should I solve this problem?

  • Prime Factor Decomposition
  • Write in simplest form
  • Solve by quadratic formula (general formula)
  • Find the derivative using the definition
  • Simplify
  • Find the integral
  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find the roots
  • Load more...
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1

Rewrite $9$ as a power

$\left(\sqrt[3]{3}+1\right)\left(\sqrt[3]{3^{2}}-\sqrt[3]{3}+1\right)$

Learn how to solve radical expressions problems step by step online.

$\left(\sqrt[3]{3}+1\right)\left(\sqrt[3]{3^{2}}-\sqrt[3]{3}+1\right)$

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Learn how to solve radical expressions problems step by step online. Simplify the expression with radicals (3^(1/3)+1)(9^(1/3)-3^(1/3)+1). Rewrite 9 as a power. Multiply the single term \sqrt[3]{3^{2}}-\sqrt[3]{3}+1 by each term of the polynomial \left(\sqrt[3]{3}+1\right). Simplify \sqrt[3]{3^{2}} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 2 and n equals \frac{1}{3}. Simplify \sqrt[3]{3^{2}} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 2 and n equals \frac{1}{3}.

Final answer to the problem

$\left(\sqrt[3]{\left(3\right)^{2}}-\sqrt[3]{3}+1\right)\sqrt[3]{3}+\sqrt[3]{\left(3\right)^{2}}-\sqrt[3]{3}+1$

Exact Numeric Answer

$4$

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Function Plot

Plotting: $\left(\sqrt[3]{\left(3\right)^{2}}-\sqrt[3]{3}+1\right)\sqrt[3]{3}+\sqrt[3]{\left(3\right)^{2}}-\sqrt[3]{3}+1$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Radical Expressions

Radical expressions are those expressions that include a radical, which is the symbol for calculating a root.

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