Final answer to the problem
$-\frac{1}{2}\cos\left(2\pi \right)- \left(-\frac{1}{2}\right)\cos\left(2\cdot 0\right)$
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Step-by-step Solution
How should I solve this problem?
- Integrate using basic integrals
- Integrate by partial fractions
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Integrate using trigonometric identities
- Product of Binomials with Common Term
- FOIL Method
- Load more...
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1
Apply the formula: $\int\sin\left(ax\right)dx$$=-\left(\frac{1}{a}\right)\cos\left(ax\right)+C$, where $a=2$
$\left[- \left(\frac{1}{2}\right)\cos\left(2x\right)\right]_{0}^{\pi }$
Learn how to solve definite integrals problems step by step online.
$\left[- \left(\frac{1}{2}\right)\cos\left(2x\right)\right]_{0}^{\pi }$
Learn how to solve definite integrals problems step by step online. Integrate the function sin(2x) from 0 to pi. Apply the formula: \int\sin\left(ax\right)dx=-\left(\frac{1}{a}\right)\cos\left(ax\right)+C, where a=2. Multiply the fraction and term in - \left(\frac{1}{2}\right)\cos\left(2x\right). Evaluate the definite integral.
Final answer to the problem
$-\frac{1}{2}\cos\left(2\pi \right)- \left(-\frac{1}{2}\right)\cos\left(2\cdot 0\right)$
