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How should I solve this problem?
- Integrate using basic integrals
- Integrate by partial fractions
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Integrate using trigonometric identities
- Product of Binomials with Common Term
- FOIL Method
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The integral of a function times a constant ($11$) is equal to the constant times the integral of the function
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$11\int\frac{1}{-3+6x^2-7x}dx$
Learn how to solve problems step by step online. Find the integral int(11/(6x^2-7x+-3))dx. The integral of a function times a constant (11) is equal to the constant times the integral of the function. Rewrite the expression \frac{1}{6x^2-7x-3} inside the integral in factored form. Rewrite the fraction \frac{1}{\left(2x-3\right)\left(3x+1\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B. The first step is to multiply both sides of the equation from the previous step by \left(2x-3\right)\left(3x+1\right).