Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Integrate by trigonometric substitution
- Solve for a
- Solve for b
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
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Divide $-5$ by $7$
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$\frac{1\frac{-\frac{5}{7}\cdot 15ab^2}{4}a^2b}{6}a^4b^3$
Learn how to solve problems step by step online. Solve the equation ((-5/7ab^2*15)/4a^2b*1)/6a^4b^3$=0$. Divide -5 by 7. Multiply -\frac{5}{7} times 15. Any expression multiplied by 1 is equal to itself. Take \frac{-\frac{75}{7}}{4} out of the fraction.