Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Integrate by parts
- Integrate by partial fractions
- Integrate by substitution
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Integrate using trigonometric identities
- Integrate using basic integrals
- Product of Binomials with Common Term
- FOIL Method
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Rewrite the fraction $\frac{y}{y^2-2y-3}$ inside the integral as the product of two functions: $y\frac{1}{y^2-2y-3}$
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$\int_{4}^{8} y\frac{1}{y^2-2y-3}dy$
Learn how to solve problems step by step online. Integrate the function y/(y^2-2y+-3) from 4 to 8. Rewrite the fraction \frac{y}{y^2-2y-3} inside the integral as the product of two functions: y\frac{1}{y^2-2y-3}. We can solve the integral \int y\frac{1}{y^2-2y-3}dy by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. First, identify or choose u and calculate it's derivative, du. Now, identify dv and calculate v.