Integrate the function $\left(x+1\right)\sqrt{10-2x}$ from 0 to $2$

Step-by-step Solution

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acosh
atanh
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asech
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Final answer to the problem

$-4.1560129+\frac{-228.0461353}{-15}$
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Step-by-step Solution

How should I solve this problem?

  • Integrate by parts
  • Integrate by partial fractions
  • Integrate by substitution
  • Integrate using tabular integration
  • Integrate by trigonometric substitution
  • Weierstrass Substitution
  • Integrate using trigonometric identities
  • Integrate using basic integrals
  • Product of Binomials with Common Term
  • FOIL Method
  • Load more...
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1

We can solve the integral $\int\left(x+1\right)\sqrt{10-2x}dx$ by applying integration by parts method to calculate the integral of the product of two functions, using the following formula

$\displaystyle\int u\cdot dv=u\cdot v-\int v \cdot du$

Learn how to solve limits by direct substitution problems step by step online.

$\displaystyle\int u\cdot dv=u\cdot v-\int v \cdot du$

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Learn how to solve limits by direct substitution problems step by step online. Integrate the function (x+1)(10-2x)^(1/2) from 0 to 2. We can solve the integral \int\left(x+1\right)\sqrt{10-2x}dx by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. First, identify or choose u and calculate it's derivative, du. Now, identify dv and calculate v. Solve the integral to find v.

Final answer to the problem

$-4.1560129+\frac{-228.0461353}{-15}$

Exact Numeric Answer

$11.047063$

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Function Plot

Plotting: $\left(x+1\right)\sqrt{10-2x}$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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