Solve the trigonometric integral $\int\sin\left(x\right)^2\cos\left(x\right)^2dx$

Step-by-step Solution

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Final answer to the problem

$-\frac{1}{2}\sin\left(2x\right)+\frac{1}{2}x-\frac{3}{8}x+\frac{-\cos\left(x\right)^{3}\sin\left(x\right)}{4}+C_0$
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Step-by-step Solution

How should I solve this problem?

  • Integrate by parts
  • Integrate by partial fractions
  • Integrate by substitution
  • Integrate using tabular integration
  • Integrate by trigonometric substitution
  • Weierstrass Substitution
  • Integrate using trigonometric identities
  • Integrate using basic integrals
  • Product of Binomials with Common Term
  • FOIL Method
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1

Rewrite the trigonometric expression $\sin\left(x\right)^2\cos\left(x\right)^2$ inside the integral

$\int\left(\cos\left(x\right)^2-\cos\left(x\right)^{4}\right)dx$

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$\int\left(\cos\left(x\right)^2-\cos\left(x\right)^{4}\right)dx$

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Unlock the first 3 steps of this solution

Learn how to solve problems step by step online. Solve the trigonometric integral int(sin(x)^2cos(x)^2)dx. Rewrite the trigonometric expression \sin\left(x\right)^2\cos\left(x\right)^2 inside the integral. Expand the integral \int\left(\cos\left(x\right)^2-\cos\left(x\right)^{4}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\cos\left(x\right)^2dx results in: \frac{1}{2}x+\frac{1}{4}\sin\left(2x\right). Gather the results of all integrals.

Final answer to the problem

$-\frac{1}{2}\sin\left(2x\right)+\frac{1}{2}x-\frac{3}{8}x+\frac{-\cos\left(x\right)^{3}\sin\left(x\right)}{4}+C_0$

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Function Plot

Plotting: $-\frac{1}{2}\sin\left(2x\right)+\frac{1}{2}x-\frac{3}{8}x+\frac{-\cos\left(x\right)^{3}\sin\left(x\right)}{4}+C_0$

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0
a
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f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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