Solve the quadratic equation $y^2-12y+32=0$

Step-by-step Solution

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Final answer to the problem

$y=4,\:y=8$
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Step-by-step Solution

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  • Find the derivative using the definition
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1

Factor the trinomial $y^2-12y+32$ finding two numbers that multiply to form $32$ and added form $-12$

$\begin{matrix}\left(-4\right)\left(-8\right)=32\\ \left(-4\right)+\left(-8\right)=-12\end{matrix}$

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$\begin{matrix}\left(-4\right)\left(-8\right)=32\\ \left(-4\right)+\left(-8\right)=-12\end{matrix}$

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Learn how to solve problems step by step online. Solve the quadratic equation y^2-12y+32=0. Factor the trinomial y^2-12y+32 finding two numbers that multiply to form 32 and added form -12. Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values. Break the equation in 2 factors and set each factor equal to zero, to obtain simpler equations. Solve the equation (1).

Final answer to the problem

$y=4,\:y=8$

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Function Plot

Plotting: $y^2-12y+32$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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