Solve the quadratic equation $x^2+2x-3=0$

Step-by-step Solution

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Final answer to the problem

$x=1,\:x=-3$
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Step-by-step Solution

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1

Factor the trinomial $x^2+2x-3$ finding two numbers that multiply to form $-3$ and added form $2$

$\begin{matrix}\left(-1\right)\left(3\right)=-3\\ \left(-1\right)+\left(3\right)=2\end{matrix}$

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$\begin{matrix}\left(-1\right)\left(3\right)=-3\\ \left(-1\right)+\left(3\right)=2\end{matrix}$

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Learn how to solve problems step by step online. Solve the quadratic equation x^2+2x+-3=0. Factor the trinomial x^2+2x-3 finding two numbers that multiply to form -3 and added form 2. Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values. Break the equation in 2 factors and set each factor equal to zero, to obtain simpler equations. Solve the equation (1).

Final answer to the problem

$x=1,\:x=-3$

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Function Plot

Plotting: $x^2+2x-3$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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