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Expand the integral $\int_{-1}^{2}\left(\left(x+4\right)^2-\left(x^2+2\right)^2\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
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$\pi +\int_{-1}^{2}\left(x+4\right)^2dx+\int_{-1}^{2}-\left(x^2+2\right)^2dx$
Learn how to solve integral calculus problems step by step online. Find the integral pi+int((x+4)^2-(x^2+2)^2)dx&-1&2. Expand the integral \int_{-1}^{2}\left(\left(x+4\right)^2-\left(x^2+2\right)^2\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{-1}^{2}\left(x+4\right)^2dx results in: 63. The integral \int_{-1}^{2}-\left(x^2+2\right)^2dx results in: -14-4\cdot \left(\frac{8}{3}+\frac{1}{3}\right). Gather the results of all integrals.