Final answer to the problem
Step-by-step Solution
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- Solve using L'Hôpital's rule
- Solve without using l'Hôpital
- Solve using limit properties
- Solve using direct substitution
- Solve the limit using factorization
- Solve the limit using rationalization
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
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We can factor the polynomial $x^3+2x^2+6x+5$ using the rational root theorem, which guarantees that for a polynomial of the form $a_nx^n+a_{n-1}x^{n-1}+\dots+a_0$ there is a rational root of the form $\pm\frac{p}{q}$, where $p$ belongs to the divisors of the constant term $a_0$, and $q$ belongs to the divisors of the leading coefficient $a_n$. List all divisors $p$ of the constant term $a_0$, which equals $5$
Next, list all divisors of the leading coefficient $a_n$, which equals $1$
The possible roots $\pm\frac{p}{q}$ of the polynomial $x^3+2x^2+6x+5$ will then be
Trying all possible roots, we found that $-1$ is a root of the polynomial. When we evaluate it in the polynomial, it gives us $0$ as a result
Now, divide the polynomial by the root we found $\left(x+1\right)$ using synthetic division (Ruffini's rule). First, write the coefficients of the terms of the numerator in descending order. Then, take the first coefficient $1$ and multiply by the factor $-1$. Add the result to the second coefficient and then multiply this by $-1$ and so on
In the last row of the division appear the new coefficients, with remainder equals zero. Now, rewrite the polynomial (a degree less) with the new coefficients, and multiplied by the factor $\left(x+1\right)$
Factor the trinomial $2x^2-x-3$ of the form $ax^2+bx+c$, first, make the product of $2$ and $-3$
Now, find two numbers that multiplied give us $-6$ and add up to $-1$
Rewrite the original expression
Factor $2x^2-3x+2x-3$ by the greatest common divisor $2$
Factor $2\left(x^2+x\right)-3x-3$ by the greatest common divisor $3$
Factor the polynomial $\left(x^2+x\right)$ by it's greatest common factor (GCF): $x$
Factor the polynomial $2x\left(x+1\right)-3\left(x+1\right)$ by it's greatest common factor (GCF): $x+1$
Simplify the fraction
Evaluate the limit $\lim_{x\to-1}\left(\frac{2x-3}{x^{2}+x+5}\right)$ by replacing all occurrences of $x$ by $-1$
Subtract the values $5$ and $-1$
Subtract the values $-2$ and $-3$
Calculate the power ${\left(-1\right)}^{2}$
Add the values $1$ and $4$
Divide $-5$ by $5$