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- Integrate by partial fractions
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Expand the fraction $\frac{x-3}{2x-3}$ into $2$ simpler fractions with common denominator $2x-3$
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$\int_{0}^{2}\left(\frac{x}{2x-3}+\frac{-3}{2x-3}\right)dx$
Learn how to solve problems step by step online. Integrate the function (x-3)/(2x-3) from 0 to 2. Expand the fraction \frac{x-3}{2x-3} into 2 simpler fractions with common denominator 2x-3. Expand the integral \int_{0}^{2}\left(\frac{x}{2x-3}+\frac{-3}{2x-3}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{0}^{2}\frac{x}{2x-3}dx results in: 1+\lim_{c\to0}\left(-\frac{3}{4}\ln\left(2c-3\right)\right). Gather the results of all integrals.