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Rewrite the expression $\frac{1}{x^2-6x+9}$ inside the integral in factored form
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$\int_{1}^{2}\frac{1}{\left(x-3\right)^{2}}dx$
Learn how to solve problems step by step online. Integrate the function 1/(x^2-6x+9) from 1 to 2. Rewrite the expression \frac{1}{x^2-6x+9} inside the integral in factored form. Apply the formula: \int\frac{n}{\left(x+a\right)^c}dx=\frac{-n}{\left(c-1\right)\left(x+a\right)^{\left(c-1\right)}}+C, where a=-3, c=2 and n=1. Simplify the expression inside the integral. Evaluate the definite integral.