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Expand the integral $\int\left(\frac{x-4}{x^2+3x}-10\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int\frac{x-4}{x^2+3x}dx+\int-10dx$
Learn how to solve problems step by step online. Integrate int((x-4)/(x^2+3x)-10)dx. Expand the integral \int\left(\frac{x-4}{x^2+3x}-10\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{x-4}{x^2+3x}dx results in: -\frac{4}{3}\ln\left(x\right)+\frac{7}{3}\ln\left(x+3\right). Gather the results of all integrals. The integral \int-10dx results in: -10x.