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- Integrate by partial fractions
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- Product of Binomials with Common Term
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Rewrite the fraction $\frac{6x+3}{\left(x^2+1\right)\left(x^2+4\right)}$ in $2$ simpler fractions using partial fraction decomposition
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$\frac{6x+3}{\left(x^2+1\right)\left(x^2+4\right)}=\frac{Ax+B}{x^2+1}+\frac{Cx+D}{x^2+4}$
Learn how to solve problems step by step online. Find the integral int((6x+3)/((x^2+1)(x^2+4)))dx. Rewrite the fraction \frac{6x+3}{\left(x^2+1\right)\left(x^2+4\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C, D. The first step is to multiply both sides of the equation from the previous step by \left(x^2+1\right)\left(x^2+4\right). Multiplying polynomials. Simplifying.