Simplify the expression $\frac{\left(x-1\right)^3}{3}$

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Final answer to the problem

$\frac{x^3-3x^2+3x-1}{3}$
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The cube of a binomial (difference) is equal to the cube of the first term, minus three times the square of the first by the second, plus three times the first by the square of the second, minus the cube of the second term. In other words: $(a-b)^3=a^3-3a^2b+3ab^2-b^3 = (x)^3+3(x)^2(-1)+3(x)(-1)^2+(-1)^3 =$

$\frac{x^3+3\cdot -1x^2+3\cdot {\left(-1\right)}^2x+{\left(-1\right)}^3}{3}$

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$\frac{x^3+3\cdot -1x^2+3\cdot {\left(-1\right)}^2x+{\left(-1\right)}^3}{3}$

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Learn how to solve simplification of algebraic fractions problems step by step online. Simplify the expression ((x-1)^3)/3. The cube of a binomial (difference) is equal to the cube of the first term, minus three times the square of the first by the second, plus three times the first by the square of the second, minus the cube of the second term. In other words: (a-b)^3=a^3-3a^2b+3ab^2-b^3 = (x)^3+3(x)^2(-1)+3(x)(-1)^2+(-1)^3 =. Multiply 3 times -1. Calculate the power {\left(-1\right)}^2. Multiply 3 times 1.

Final answer to the problem

$\frac{x^3-3x^2+3x-1}{3}$

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Plotting: $\frac{x^3-3x^2+3x-1}{3}$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Simplification of algebraic fractions

Simplification or reduction of algebraic fractions is the action of dividing the numerator and denominator of a fraction by a common factor in order to obtain another much simpler equivalent fraction. We can say that a fraction is reduced to its simplest when there is no common factor between the numerator and the denominator.

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