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Divide $9x^3-8x^2-4x+48$ by $x^2-4$
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$\begin{array}{l}\phantom{\phantom{;}x^{2}-4;}{\phantom{;}9x\phantom{;}-8\phantom{;}\phantom{;}}\\\phantom{;}x^{2}-4\overline{\smash{)}\phantom{;}9x^{3}-8x^{2}-4x\phantom{;}+48\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}-4;}\underline{-9x^{3}\phantom{-;x^n}+36x\phantom{;}\phantom{-;x^n}}\\\phantom{-9x^{3}+36x\phantom{;};}-8x^{2}+32x\phantom{;}+48\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-4-;x^n;}\underline{\phantom{;}8x^{2}\phantom{-;x^n}-32\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}8x^{2}-32\phantom{;}\phantom{;}-;x^n;}\phantom{;}32x\phantom{;}+16\phantom{;}\phantom{;}\\\end{array}$
Learn how to solve problems step by step online. Find the integral int((9x^3-8x^2-4x+48)/(x^2-4))dx. Divide 9x^3-8x^2-4x+48 by x^2-4. Resulting polynomial. Expand the integral \int\left(9x-8+\frac{32x+16}{x^2-4}\right)dx into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int9xdx results in: \frac{9}{2}x^2.