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Integrate the function $\frac{15+2x^3}{x^4}$ from $1$ to $3$

Step-by-step Solution

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Final Answer

$\frac{582}{83}$
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Step-by-step Solution

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Expand the fraction $\frac{15+2x^3}{x^4}$ into $2$ simpler fractions with common denominator $x^4$

$\int_{1}^{3}\left(\frac{15}{x^4}+\frac{2x^3}{x^4}\right)dx$

Learn how to solve definite integrals problems step by step online.

$\int_{1}^{3}\left(\frac{15}{x^4}+\frac{2x^3}{x^4}\right)dx$

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Learn how to solve definite integrals problems step by step online. Integrate the function (15+2x^3)/(x^4) from 1 to 3. Expand the fraction \frac{15+2x^3}{x^4} into 2 simpler fractions with common denominator x^4. Simplify the resulting fractions. Expand the integral \int_{1}^{3}\left(\frac{15}{x^4}+\frac{2}{x}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{1}^{3}\frac{15}{x^4}dx results in: \frac{130}{27}.

Final Answer

$\frac{582}{83}$

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Function Plot

Plotting: $\frac{15+2x^3}{x^4}$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

Used Formulas

2. See formulas

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