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# Solve the quadratic equation $-31x^2+448x+896=0$

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##  Final answer to the problem

$x=\frac{255}{31}$
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##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Solve for x
• Find the derivative using the definition
• Solve by quadratic formula (general formula)
• Simplify
• Find the integral
• Find the derivative
• Factor
• Factor by completing the square
• Find the roots
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1

Use the complete the square method to factor the trinomial of the form $ax^2+bx+c$. Take common factor $a$ ($-31$) to all terms

$-31\left(x^2-\frac{448}{31}x-\frac{896}{31}\right)=0$

Learn how to solve quadratic equations problems step by step online.

$-31\left(x^2-\frac{448}{31}x-\frac{896}{31}\right)=0$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation -31x^2+448x+896=0. Use the complete the square method to factor the trinomial of the form ax^2+bx+c. Take common factor a (-31) to all terms. Add and subtract \displaystyle\left(\frac{b}{2a}\right)^2. Factor the perfect square trinomial x^2+-\frac{448}{31}x+\frac{50176}{961}. Multiply the fraction and term in - \frac{224}{31}.

##  Final answer to the problem

$x=\frac{255}{31}$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: Quadratic Equations

The quadratic equations (or second degree equations) are those equations where the greatest exponent to which the unknown is raised is the exponent 2.