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# Solve the quadratic equation $-31x^2+448x+896=0$

## Step-by-step Solution

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$x=16.232221,\:x=-1.780608$
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##  Step-by-step Solution 

Problem to solve:

$-31x^2+448x+896=0$

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For a simpler handling of the equation, change the sign of all terms, multiplying the entire whole by $-1$

$31x^2-448x-896=0$

Learn how to solve quadratic equations problems step by step online.

$31x^2-448x-896=0$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation -31x^2+448x+896=0. For a simpler handling of the equation, change the sign of all terms, multiplying the entire whole by -1. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=31, b=-448 and c=-896. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplify \frac{448\pm \sqrt{{\left(-448\right)}^2-4\cdot 31\cdot -896}}{2\cdot 31}. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-).

$x=16.232221,\:x=-1.780608$

##  Explore different ways to solve this problem

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asinh
acosh
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