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# Integrate the function $\frac{x^2-4}{x-2}$ from $-1$ to $1$

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e
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ln
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log
lim
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θ
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sin
cos
tan
cot
sec
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asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

##  Final Answer

$4$
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##  Step-by-step Solution 

Specify the solving method

1

Rewrite the expression $\frac{x^2-4}{x-2}$ inside the integral in factored form

$\int_{-1}^{1}\left(x+2\right)dx$

Learn how to solve definite integrals problems step by step online.

$\int_{-1}^{1}\left(x+2\right)dx$

Learn how to solve definite integrals problems step by step online. Integrate the function (x^2-4)/(x-2) from -1 to 1. Rewrite the expression \frac{x^2-4}{x-2} inside the integral in factored form. Expand the integral \int_{-1}^{1}\left(x+2\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{-1}^{1} xdx results in: 0. The integral \int_{-1}^{1}2dx results in: 4.

##  Final Answer

$4$

##  Exact Numeric Answer

$4$

##  Explore different ways to solve this problem

SnapXam A2

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

### Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

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