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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=10$, $b=9$ and $c=12$. Then substitute the values of the coefficients of the equation in the quadratic formula:
- $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$x=\frac{-9+\pm \sqrt{-399}}{20}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 10x^2+9x+12=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=10, b=9 and c=12. Then substitute the values of the coefficients of the equation in the quadratic formula:<ul><li>\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}</li></ul>. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Calculate the power \sqrt{-399} using complex numbers. Calculate the power \sqrt{-399} using complex numbers.