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# Solve the equation $\left(x+1\right)\left(x-2\right)\left(x+3+1\right)=0$

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##  Final answer to the problem

$x=-1,\:x=2,\:x=-4$
Got another answer? Verify it here!

##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Solve for x
• Find the derivative using the definition
• Solve by quadratic formula (general formula)
• Simplify
• Find the integral
• Find the derivative
• Factor
• Factor by completing the square
• Find the roots
Can't find a method? Tell us so we can add it.
1

Add the values $3$ and $1$

$\left(x+1\right)\left(x-2\right)\left(x+4\right)=0$

Learn how to solve one-variable linear equations problems step by step online.

$\left(x+1\right)\left(x-2\right)\left(x+4\right)=0$

Learn how to solve one-variable linear equations problems step by step online. Solve the equation (x+1)(x-2)(x+3+1)=0. Add the values 3 and 1. Break the equation in 3 factors and set each equal to zero, to obtain. Solve the equation (1). We need to isolate the dependent variable x, we can do that by simultaneously subtracting 1 from both sides of the equation.

##  Final answer to the problem

$x=-1,\:x=2,\:x=-4$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: One-variable linear equations

Algebraic equations that have just one variable.