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$x^2+3x<10$
Learn how to solve inequalities problems step by step online. Solve the inequality x^2<10-3x. Grouping terms. Factor the polynomial x^2+3x. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value 3. Now, we can factor x^2+3x+\frac{9}{4} as a squared binomial of the form \left(x+\frac{b}{2}\right)^2. Moving the term -\frac{9}{4} to the other side of the inequation with opposite sign.