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The product of two binomials of the form $(x+a)(x+b)$ is equal to the product of the first terms of the binomials, plus the algebraic sum of the second terms by the common term of the binomials, plus the product of the second terms of the binomials. In other words: $(x+a)(x+b)=x^2+(a+b)x+ab$
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$x^2+x\left(-2+1\right)-2\cdot 1>0$
Learn how to solve one-variable linear inequalities problems step by step online. Solve the inequality (x-2)(x+1)>0. The product of two binomials of the form (x+a)(x+b) is equal to the product of the first terms of the binomials, plus the algebraic sum of the second terms by the common term of the binomials, plus the product of the second terms of the binomials. In other words: (x+a)(x+b)=x^2+(a+b)x+ab. Subtract the values 1 and -2. Multiply -2 times 1. Moving the term -2 to the other side of the inequation with opposite sign.