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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=13$, $b=24$ and $c=-304$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$q=\frac{-24+\pm 128}{26}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 13q^2+24q-304=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=13, b=24 and c=-304. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 128 and -24. Subtract the values -24 and -128.