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The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$
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$\log_{25}\left(1\right)-\log_{25}\left(5\right)$
Learn how to solve algebraic expressions problems step by step online. Expand the logarithmic expression log25((1/5)). The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). Evaluating the logarithm of base 25 of 1. Evaluating the logarithm of base 25 of 5. Multiply -1 times \frac{1}{2}.