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Rewrite the expression $\left(4x^3-6x^2\right)^3\left(6x-6\right)$ inside the integral in factored form
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$\int48x^{6}\left(2x-3\right)^3\left(x-1\right)dx$
Learn how to solve problems step by step online. Find the integral int((4x^3-6x^2)^3(6x-6))dx. Rewrite the expression \left(4x^3-6x^2\right)^3\left(6x-6\right) inside the integral in factored form. Multiplying polynomials x^{6} and x-1. Multiplying polynomials 48 and x^{6}x-x^{6}. The cube of a binomial (difference) is equal to the cube of the first term, minus three times the square of the first by the second, plus three times the first by the square of the second, minus the cube of the second term. In other words: (a-b)^3=a^3-3a^2b+3ab^2-b^3 = (2x)^3+3(2x)^2(-3)+3(2x)(-3)^2+(-3)^3 =.