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Solve the quadratic equation $\frac{669}{4}x^2-\frac{161163}{500}x+\frac{28311}{250}=0$

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 Final Answer

$x=1.465044,\:x=0.462166$
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 Step-by-step Solution 

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Divide $669$ by $4$

$\frac{669}{4}x^2-\frac{161163}{500}x+\frac{28311}{250}=0$

Learn how to solve quadratic equations problems step by step online.

$\frac{669}{4}x^2-\frac{161163}{500}x+\frac{28311}{250}=0$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 669/4x^2+-161163/500x28311/250=0. Divide 669 by 4. Divide -161163 by 500. Divide 28311 by 250. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=\frac{669}{4}, b=-322.326 and c=113.244. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

 Final Answer

$x=1.465044,\:x=0.462166$

 Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve for xFind the rootsSolve by factoringSolve by completing the squareSolve by quadratic formula (general formula)Find break even pointsFind the discriminant

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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

Main Topic: Quadratic Equations

The quadratic equations (or second degree equations) are those equations where the greatest exponent to which the unknown is raised is the exponent 2.

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