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Find the implicit derivative $\frac{d}{dx}\left(\sqrt[3]{a+x^2}+\sqrt[3]{b+y^2}=\sqrt[3]{cx}\right)$

Step-by-step Solution

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Final Answer

$\frac{2x}{3\sqrt[3]{\left(a+x^2\right)^{2}}}+\frac{2}{3\sqrt[3]{\left(b+y^2\right)^{2}}}y\cdot y^{\prime}=\frac{\sqrt[3]{c}}{3\sqrt[3]{x^{2}}}$
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Step-by-step Solution

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Apply implicit differentiation by taking the derivative of both sides of the equation with respect to the differentiation variable

$\frac{d}{dx}\left(\sqrt[3]{a+x^2}+\sqrt[3]{b+y^2}\right)=\frac{d}{dx}\left(\sqrt[3]{cx}\right)$

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$\frac{d}{dx}\left(\sqrt[3]{a+x^2}+\sqrt[3]{b+y^2}\right)=\frac{d}{dx}\left(\sqrt[3]{cx}\right)$

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Learn how to solve problems step by step online. Find the implicit derivative d/dx((a+x^2)^1/3+(b+y^2)^1/3=(cx)^1/3). Apply implicit differentiation by taking the derivative of both sides of the equation with respect to the differentiation variable. The power rule for differentiation states that if n is a real number and f(x) = x^n, then f'(x) = nx^{n-1}. The derivative of a function multiplied by a constant is equal to the constant times the derivative of the function. The derivative of the linear function is equal to 1.

Final Answer

$\frac{2x}{3\sqrt[3]{\left(a+x^2\right)^{2}}}+\frac{2}{3\sqrt[3]{\left(b+y^2\right)^{2}}}y\cdot y^{\prime}=\frac{\sqrt[3]{c}}{3\sqrt[3]{x^{2}}}$

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Function Plot

Plotting: $\frac{2x}{3\sqrt[3]{\left(a+x^2\right)^{2}}}+\frac{2}{3\sqrt[3]{\left(b+y^2\right)^{2}}}y\cdot y^{\prime}=\frac{\sqrt[3]{c}}{3\sqrt[3]{x^{2}}}$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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