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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=21$, $b=12$ and $c=-10$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$x=\frac{-12\pm \sqrt{12^2-4\cdot 21\cdot -10}}{2\cdot 21}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 21x^2+12x-10=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=21, b=12 and c=-10. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplify \frac{-12\pm \sqrt{12^2-4\cdot 21\cdot -10}}{2\cdot 21}. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 31.368774 and -12.