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Solve the quadratic equation $2x^2-6x-3=0$

Step-by-step Solution

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Final answer to the problem

$x=3.4364917,\:x=-0.4364917$
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Step-by-step Solution

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  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
  • Simplify
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  • Find the derivative
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  • Factor by completing the square
  • Find the roots
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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=2$, $b=-6$ and $c=-3$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{6\pm \sqrt{{\left(-6\right)}^2-4\cdot 2\cdot -3}}{2\cdot 2}$

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$x=\frac{6\pm \sqrt{{\left(-6\right)}^2-4\cdot 2\cdot -3}}{2\cdot 2}$

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Learn how to solve problems step by step online. Solve the quadratic equation 2x^2-6x+-3=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=2, b=-6 and c=-3. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 6 and -7.7459667.

Final answer to the problem

$x=3.4364917,\:x=-0.4364917$

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Function Plot

Plotting: $2x^2-6x-3$

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0
a
b
c
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f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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