# Integrate -1x^2-1x^2+2x from 1/4 to 3/4

## Answer

$\frac{11}{48}$

## Step-by-step explanation

Problem

$\int_{\frac{1}{4}}^{\frac{3}{4}}\left(2x-x^2-x^2\right)dx$

1

The integral of a sum of two or more functions is equal to the sum of their integrals

$\int_{\frac{1}{4}}^{\frac{3}{4}}-x^2dx+\int_{\frac{1}{4}}^{\frac{3}{4}}-x^2dx+\int_{\frac{1}{4}}^{\frac{3}{4}}2xdx$

## Answer

$\frac{11}{48}$