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Rewrite the expression $\frac{u+3}{2u^3-8u}$ inside the integral in factored form
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$\int\frac{u+3}{2u\left(u+2\right)\left(u-2\right)}du$
Learn how to solve problems step by step online. Find the integral int((u+3)/(2u^3-8u))du. Rewrite the expression \frac{u+3}{2u^3-8u} inside the integral in factored form. Take the constant \frac{1}{2} out of the integral. Rewrite the fraction \frac{u+3}{u\left(u+2\right)\left(u-2\right)} in 3 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by u\left(u+2\right)\left(u-2\right).