ðŸ‘‰ Try now NerdPal! Our new math app on iOS and Android

# Solve the equation $\left(y-2\right)\left(3y-1\right)=1000$

Go!
Symbolic mode
Text mode
Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

##  Final answer to the problem

$y=\frac{7+\sqrt{12025}}{6},\:y=\frac{7-\sqrt{12025}}{6}$
Got another answer? Verify it here!

##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Solve for y
• Find the derivative using the definition
• Solve by quadratic formula (general formula)
• Simplify
• Find the integral
• Find the derivative
• Factor
• Factor by completing the square
• Find the roots
Can't find a method? Tell us so we can add it.
1

Multiplying polynomials $y-2$ and $3y-1$

$3\left(y-2\right)y-\left(y-2\right)=1000$

Learn how to solve one-variable linear equations problems step by step online.

$3\left(y-2\right)y-\left(y-2\right)=1000$

Learn how to solve one-variable linear equations problems step by step online. Solve the equation (y-2)(3y-1)=1000. Multiplying polynomials y-2 and 3y-1. Simplify the product -(y-2). Move everything to the left hand side of the equation. Subtract the values 2 and -1000.

##  Final answer to the problem

$y=\frac{7+\sqrt{12025}}{6},\:y=\frac{7-\sqrt{12025}}{6}$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: One-variable linear equations

Algebraic equations that have just one variable.