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Rewrite the integrand $\left(\sin\left(x\right)-2\right)^2$ in expanded form
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$\int_{0}^{\pi }\left(\sin\left(x\right)^2-4\sin\left(x\right)+4\right)dx$
Learn how to solve definite integrals problems step by step online. Integrate the function (sin(x)-2)^2 from 0 to pi. Rewrite the integrand \left(\sin\left(x\right)-2\right)^2 in expanded form. Expand the integral \int_{0}^{\pi }\left(\sin\left(x\right)^2-4\sin\left(x\right)+4\right)dx into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{0}^{\pi }\sin\left(x\right)^2dx results in: \frac{\pi}{2}. The integral \int_{0}^{\pi }-4\sin\left(x\right)dx results in: -8.