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The trinomial $\tan\left(x\right)^2+6\tan\left(x\right)\sec\left(x\right)+9\sec\left(x\right)^2$ is a perfect square trinomial, because it's discriminant is equal to zero
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$\Delta=b^2-4ac=6^2-4\left(1\right)\left(9\right) = 0$
Learn how to solve problems step by step online. Simplify the trigonometric expression (tan(x)^2+6tan(x)sec(x)9sec(x)^2)/(tan(x)+3sec(x)). The trinomial \tan\left(x\right)^2+6\tan\left(x\right)\sec\left(x\right)+9\sec\left(x\right)^2 is a perfect square trinomial, because it's discriminant is equal to zero. Using the perfect square trinomial formula. Factoring the perfect square trinomial. Simplify the fraction \frac{\left(\tan\left(x\right)+3\sec\left(x\right)\right)^{2}}{\tan\left(x\right)+3\sec\left(x\right)} by \tan\left(x\right)+3\sec\left(x\right).