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Solve the quadratic equation $-\frac{1}{80}x^2+x-15=0$

Step-by-step Solution

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Final Answer

$x=60,\:x=20$
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Step-by-step Solution

Problem to solve:

$-\frac{1}{80}x^2+x-15=0$

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1

For a simpler handling of the equation, change the sign of all terms, multiplying the entire whole by $-1$

$\frac{1}{80}x^2-x+15=0$

Learn how to solve differential calculus problems step by step online.

$\frac{1}{80}x^2-x+15=0$

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Learn how to solve differential calculus problems step by step online. Solve the quadratic equation -1/80x^2+x-15=0. For a simpler handling of the equation, change the sign of all terms, multiplying the entire whole by -1. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=\frac{1}{80}, b=-1 and c=15. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-).

Final Answer

$x=60,\:x=20$

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Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve for xFind the rootsSolve by factoringSolve by completing the squareSolve by quadratic formulaFind break even pointsFind the discriminant

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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