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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=4$, $b=15$ and $c=9$. Then substitute the values of the coefficients of the equation in the quadratic formula:
- $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$x=\frac{-15+\pm 9}{8}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 4x^2+15x+9=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=4, b=15 and c=9. Then substitute the values of the coefficients of the equation in the quadratic formula:<ul><li>\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}</li></ul>. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 9 and -15. Subtract the values -15 and -9.