# Find the derivative of (x^2y^2)/(x^4+y^4)

## \frac{d}{dx}\left(\frac{x^2 y^2}{x^4+y^4}\right)

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$\frac{2x\left(y^4+x^4\right)y^2-4y^2x^2x^{3}}{\left(y^4+x^4\right)^2}$

## Step by step solution

Problem

$\frac{d}{dx}\left(\frac{x^2 y^2}{x^4+y^4}\right)$
1

Applying the quotient rule which states that if $f(x)$ and $g(x)$ are functions and $h(x)$ is the function defined by ${\displaystyle h(x) = \frac{f(x)}{g(x)}}$, where ${g(x) \neq 0}$, then ${\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}$

$\frac{\left(y^4+x^4\right)\frac{d}{dx}\left(y^2x^2\right)-y^2x^2\frac{d}{dx}\left(y^4+x^4\right)}{\left(y^4+x^4\right)^2}$
2

The derivative of a function multiplied by a constant is equal to the constant times the derivative of the function

$\frac{\left(y^4+x^4\right)y^2\frac{d}{dx}\left(x^2\right)-y^2x^2\frac{d}{dx}\left(y^4+x^4\right)}{\left(y^4+x^4\right)^2}$
3

The power rule for differentiation states that if $n$ is a real number and $f(x) = x^n$, then $f'(x) = nx^{n-1}$

$\frac{2x\left(y^4+x^4\right)y^2-y^2x^2\frac{d}{dx}\left(y^4+x^4\right)}{\left(y^4+x^4\right)^2}$
4

The derivative of a sum of two functions is the sum of the derivatives of each function

$\frac{2x\left(y^4+x^4\right)y^2-y^2x^2\left(\frac{d}{dx}\left(y^4\right)+\frac{d}{dx}\left(x^4\right)\right)}{\left(y^4+x^4\right)^2}$
5

The derivative of the constant function is equal to zero

$\frac{2x\left(y^4+x^4\right)y^2-y^2x^2\left(0+\frac{d}{dx}\left(x^4\right)\right)}{\left(y^4+x^4\right)^2}$
6

The power rule for differentiation states that if $n$ is a real number and $f(x) = x^n$, then $f'(x) = nx^{n-1}$

$\frac{2x\left(y^4+x^4\right)y^2-\left(0+4x^{3}\right)y^2x^2}{\left(y^4+x^4\right)^2}$
7

$x+0=x$, where $x$ is any expression

$\frac{2x\left(y^4+x^4\right)y^2-1\cdot 4y^2x^2x^{3}}{\left(y^4+x^4\right)^2}$
8

Multiply $4$ times $-1$

$\frac{2x\left(y^4+x^4\right)y^2-4y^2x^2x^{3}}{\left(y^4+x^4\right)^2}$

$\frac{2x\left(y^4+x^4\right)y^2-4y^2x^2x^{3}}{\left(y^4+x^4\right)^2}$

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### Main topic:

Differential calculus

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