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Factor the difference of squares $x^2-25$ as the product of two conjugated binomials
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$\frac{x-5}{\left(x+5\right)\left(x-5\right)}$
Learn how to solve limits by direct substitution problems step by step online. Find the limit (x)->(5)lim((x-5)/(x^2-25)). Factor the difference of squares x^2-25 as the product of two conjugated binomials. Simplify the fraction \frac{x-5}{\left(x+5\right)\left(x-5\right)} by x-5. Evaluate the limit \lim_{x\to5}\left(\frac{1}{x+5}\right) by replacing all occurrences of x by 5. Add the values 5 and 5.