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# Find the limit of $\frac{x^2+6x+5}{x^2-2x-3}$ as $x$ approaches $-1$

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##  Final answer to the problem

$-1$
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##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Solve using L'Hôpital's rule
• Solve without using l'Hôpital
• Solve using limit properties
• Solve using direct substitution
• Solve the limit using factorization
• Solve the limit using rationalization
• Integrate by partial fractions
• Product of Binomials with Common Term
• FOIL Method
Can't find a method? Tell us so we can add it.
1

Factor the trinomial $x^2-2x-3$ finding two numbers that multiply to form $-3$ and added form $-2$

$\begin{matrix}\left(1\right)\left(-3\right)=-3\\ \left(1\right)+\left(-3\right)=-2\end{matrix}$

Learn how to solve limits by direct substitution problems step by step online.

$\begin{matrix}\left(1\right)\left(-3\right)=-3\\ \left(1\right)+\left(-3\right)=-2\end{matrix}$

Learn how to solve limits by direct substitution problems step by step online. Find the limit of (x^2+6x+5)/(x^2-2x+-3) as x approaches -1. Factor the trinomial x^2-2x-3 finding two numbers that multiply to form -3 and added form -2. Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values. Factor the trinomial x^2+6x+5 finding two numbers that multiply to form 5 and added form 6. Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values.

##  Final answer to the problem

$-1$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: Limits by Direct Substitution

Find limits of functions at a specific point by directly plugging the value into the function.

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