Find the integral $\int\sec\left(\frac{1}{3}\right)xx^2dx$

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Final answer to the problem

$\frac{\sec\left(\frac{1}{3}\right)x^{4}}{4}+C_0$
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Step-by-step Solution

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When multiplying exponents with same base you can add the exponents: $\sec\left(\frac{1}{3}\right)xx^2$

$\int\sec\left(\frac{1}{3}\right)x^{3}dx$

Learn how to solve differential calculus problems step by step online.

$\int\sec\left(\frac{1}{3}\right)x^{3}dx$

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Learn how to solve differential calculus problems step by step online. Find the integral int(xsec(1/3)x^2)dx. When multiplying exponents with same base you can add the exponents: \sec\left(\frac{1}{3}\right)xx^2. The integral of a function times a constant (\sec\left(\frac{1}{3}\right)) is equal to the constant times the integral of the function. Apply the power rule for integration, \displaystyle\int x^n dx=\frac{x^{n+1}}{n+1}, where n represents a number or constant function, such as 3. Multiplying the fraction by \sec\left(\frac{1}{3}\right).

Final answer to the problem

$\frac{\sec\left(\frac{1}{3}\right)x^{4}}{4}+C_0$

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Plotting: $\frac{\sec\left(\frac{1}{3}\right)x^{4}}{4}+C_0$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

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