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# Solve the quadratic equation $6x^2+15x+5=0$

## Step-by-step Solution

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###  Videos

$x=-0.396087,\:x=-2.103913$
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##  Step-by-step Solution 

Problem to solve:

$6x^2+15x+5=0$

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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=6$, $b=15$ and $c=5$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-15\pm \sqrt{15^2-4\cdot 6\cdot 5}}{2\cdot 6}$

Learn how to solve quadratic equations problems step by step online.

$x=\frac{-15\pm \sqrt{15^2-4\cdot 6\cdot 5}}{2\cdot 6}$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 6x^2+15x+5=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=6, b=15 and c=5. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplify \frac{-15\pm \sqrt{15^2-4\cdot 6\cdot 5}}{2\cdot 6}. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 10.246951 and -15.

$x=-0.396087,\:x=-2.103913$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve for xFind the rootsSolve by factoringSolve by completing the squareSolve by quadratic formulaFind break even points

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log
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d/dx
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sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
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acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

~ 0.03 s

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