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Solve the quadratic equation $12x^2-19x-21=0$

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 Final answer to the problem

$x=\frac{7}{3},\:x=-\frac{3}{4}$
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 Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Solve for x
• Find the derivative using the definition
• Solve by quadratic formula (general formula)
• Simplify
• Find the integral
• Find the derivative
• Factor
• Factor by completing the square
• Find the roots
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Factor the trinomial $12x^2-19x-21$ of the form $ax^2+bx+c$, first, make the product of $12$ and $-21$

$\left(12\right)\left(-21\right)=-252$

Learn how to solve quadratic equations problems step by step online.

$\left(12\right)\left(-21\right)=-252$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 12x^2-19x+-21=0. Factor the trinomial 12x^2-19x-21 of the form ax^2+bx+c, first, make the product of 12 and -21. Now, find two numbers that multiplied give us -252 and add up to -19. Rewrite the original expression. Factor 12x^2-28x+9x-21 by the greatest common divisor 4.

 Final answer to the problem

$x=\frac{7}{3},\:x=-\frac{3}{4}$

 Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

beta Got a different answer? Verify it!

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

The quadratic equations (or second degree equations) are those equations where the greatest exponent to which the unknown is raised is the exponent 2.