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Expand the integral $\int_{0}^{1}\left(e^x-e\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int_{0}^{1} e^xdx+\int_{0}^{1}-edx$
Learn how to solve definite integrals problems step by step online. Integrate the function e^x-e from 0 to 1. Expand the integral \int_{0}^{1}\left(e^x-e\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{0}^{1} e^xdx results in: 1.718282. The integral \int_{0}^{1}-edx results in: -e. Gather the results of all integrals.