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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=1$, $b=-\frac{228}{25}$ and $c=\frac{847}{100}$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$x=\frac{\frac{228}{25}+\pm 7.020997}{2}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation x^2-228/25x847/100=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=-\frac{228}{25} and c=\frac{847}{100}. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values \frac{228}{25} and -7.020997. Add the values \frac{228}{25} and 7.020997.