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Solve the equation with radicals $2\left(\sqrt{x}\right)^2-1-\sqrt{x}=0$

Step-by-step Solution

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Final Answer

$x=1$
Got another answer? Verify it here!

Step-by-step Solution

Specify the solving method

1

We can try to factor the expression $2\left(\sqrt{x}\right)^2-1-\sqrt{x}$ by applying the following substitution

$u=\sqrt{x}$
2

Substituting in the polynomial, the expression results in

$2u^2-1-u$
3

Factor the trinomial $2u^2-1-u$ of the form $ax^2+bx+c$, first, make the product of $2$ and $-1$

$\left(2\right)\left(-1\right)=-2$
4

Now, find two numbers that multiplied give us $-2$ and add up to $-1$

$\begin{matrix}\left(1\right)\left(-2\right)=-2\\ \left(1\right)+\left(-2\right)=-1\end{matrix}$
5

Rewrite the original expression

$2u^2-1+u-2u$
6

Factor $2u^2-1+u-2u$ by the greatest common divisor $2$

$2\left(u^2-u\right)-1+u$
7

Factoring by $u$

$2u\left(u-1\right)-1+u$
8

Factoring by $u-1$

$\left(-1+u\right)\left(2u+1\right)$
9

Replace $u$ with the value that was assigned to it: $\sqrt{x}$

$\left(-1+\sqrt{x}\right)\left(2\sqrt{x}+1\right)=0$
10

Break the equation in $2$ factors and set each equal to zero, to obtain

$-1+\sqrt{x}=0,\:2\sqrt{x}+1=0$
11

Solve the equation ($1$)

$-1+\sqrt{x}=0$
12

We need to isolate the dependent variable , we can do that by simultaneously subtracting $-1$ from both sides of the equation

$\sqrt{x}=-1\cdot -1$
13

Multiply $-1$ times $-1$

$\sqrt{x}=1$
14

Removing the variable's exponent raising both sides of the equation to the power of $2$

$x=1$
15

Solve the equation ($2$)

$2\sqrt{x}+1=0$
16

Combining all solutions, the $2$ solutions of the equation are

$x=1,\:2\sqrt{x}+1=0$

Verify that the solutions obtained are valid in the initial equation

17

The valid solutions to the equation are the ones that, when replaced in the original equation, don't result in any square root of a negative number and make both sides of the equation equal to each other

$x=1$

Final Answer

$x=1$

Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve for xFind the rootsSolve by factoringSolve by completing the squareSolve by quadratic formula (general formula)Find break even pointsFind the discriminant

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Function Plot

Plotting: $2\left(\sqrt{x}\right)^2-1-\sqrt{x}$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Equations with Square Roots

Those equations that they degree (greatest exponent) equals 2.

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